SENDXMPPHandler-for-Python-.../ sendxmpp_handler.py

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#!/usr/bin/env python3
# app/sendxmpp_handler.py
from logging import Handler
from os import popen
class SENDXMPPHandler(Handler):
def __init__(
self,
logging_xmpp_server,
logging_xmpp_sender,
logging_xmpp_password,
logging_xmpp_recipient,
logging_xmpp_command,
logging_xmpp_use_tls
):
Handler.__init__(self)
self.logging_xmpp_server = logging_xmpp_server
self.logging_xmpp_sender = logging_xmpp_sender
self.logging_xmpp_password = logging_xmpp_password
self.logging_xmpp_recipient = logging_xmpp_recipient
self.logging_xmpp_command = logging_xmpp_command
self.logging_xmpp_use_tls = logging_xmpp_use_tls
'''
This works on Debian 10 with flask running under gunicorn3 as a systemd service, hack as necessary
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echo '<message>' | /usr/bin/sendxmpp -t -u <sender> -j <server> -p <password> <recipient@example.com>
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'''
def emit(self, record):
try:
message = self.format(record)
shell_command = "echo '{}' | {} -u {} -j {} -p {} {}".format(
message,
self.logging_xmpp_command,
self.logging_xmpp_sender,
self.logging_xmpp_server,
self.logging_xmpp_password,
self.logging_xmpp_recipient
)
if self.logging_xmpp_use_tls == '1':
shell_command += ' -t'
p = popen(shell_command, "w")
status = p.close()
if status:
print("sendxmpp_handler exit status", status)
except Exception:
self.handleError(record)